document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865160>Question 865160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> g(x)=9-2x^2\r<BR>\n" );
document.write( "\n" );
document.write( "use the discriminant to determine whether the function has complex zeros </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521563 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Real numbers are complex by definition, so g(x) has complex zeros.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Rewriting g(x) as -2x^2 + 0x + 9, the discriminant is 0^2 - 4(-2)(9) > 0, so the complex roots of g are also real (x = +/- sqrt(9/2)). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );