document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865099>Question 865099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi could i please have help with the question (8ii) in the following link of an exam past question. Thank you \r<BR>\n" );
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document.write( "http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w10_qp_13.pdf </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521554 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28465%2C300%2C-4.5%2C11%2C-0.5%2C9.5%2C%0D%0Aline%280%2C0%2C10%2C0%29%2Cline%28-3.62%2C9.32%2C6.38%2C9.32%29%2C%0D%0Aline%280%2C0%2C-3.62%2C9.32%29%2Cline%2810%2C0%2C6.38%2C9.32%29%2C%0D%0Aline%28-3.62%2C9.32%2C10%2C0%29%2C%0D%0Aarc%2810%2C0%2C20%2C20%2C180%2C248.755%29%2C%0D%0Aarc%28-3.62%2C9.32%2C20%2C20%2C0%2C68.755%29%2C%0D%0Alocate%28-4%2C9.5%2CA%29%2Clocate%286.5%2C9.5%2CB%29%2C%0D%0Alocate%28-0.4%2C0%2CD%29%2Clocate%2810.15%2C0%2CC%29%2C%0D%0Alocate%281.75%2C5.6%2CP%29%2Clocate%284.63%2C3.62%2CQ%29%2C%0D%0Agreen%28line%280%2C0%2C6.38%2C9.32%29%29%2Cgreen%28circle%283.18%2C4.66%2C0.1%29%29%2C%0D%0Alocate%283.18%2C4.6%2Cgreen%28M%29%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > You could just use Geometry and Trigonometry.<BR>\n" );
document.write( "Because the figure involves a rhombus and arcs of circles with a rhombus side as a radius,<BR>\n" );
document.write( "AQ = AB = AD = BC = DC = PC = 5 cm<BR>\n" );
document.write( "and angle BAD = 1.2 radians.<BR>\n" );
document.write( "AMB is a right triangle, with an angle at A that measures <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.2%2F2=0.6 ALIGN=MIDDLE  ALT=\"1.2%2F2=0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" > radians.<BR>\n" );
document.write( "AM = ABcos(0.6)<BR>\n" );
document.write( "PM = MQ = AQ - AM = AB - ABcos(0.6) = AB(1-cos(0.6))<BR>\n" );
document.write( "PQ = PM + MQ = 2MQ = 2AB(1-cos(0.6))<BR>\n" );
document.write( "Since AB = 5 cm, the length of PQ, in cm, is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A5%2Acos%280.6%29=1.7466 ALIGN=MIDDLE  ALT=\"2%2A5%2Acos%280.6%29=1.7466\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28rounded%29=highlight%281.75%29 ALIGN=MIDDLE  ALT=\"%28rounded%29=highlight%281.75%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%22%28+rounded%22 ALIGN=MIDDLE  ALT=\"%22%28+rounded%22\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=to ALIGN=MIDDLE  ALT=\"to\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3 ALIGN=MIDDLE  ALT=\"3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=significant ALIGN=MIDDLE  ALT=\"significant\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%22figures+%29%22 ALIGN=MIDDLE  ALT=\"%22figures+%29%22\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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