document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=865172>Question 865172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the capacity of this shape?\r<BR>\n" );
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document.write( "The answer at the back of the book is 313.45m^3\r<BR>\n" );
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document.write( "Please explain in detail and also give the solution.Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521551 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It's a cylinder, r = 2.35 and h = 14.15<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+pi%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"Vol+=+pi%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Plus 1/2 a sphere, r = 2.35<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+2pi%2Ar%5E3%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+2pi%2Ar%5E3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > for the 1/2<BR>\n" );
document.write( "Add the 2 volumes<BR>\n" );
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