document.write( "Question 865124: you are planning a rectangular patio with length that is 7 ft less than three times its width.The area of the patio is 120 ft^2. What are the dimensions of the patio \n" ); document.write( "

Algebra.Com's Answer #521516 by mananth(16946) $\"\"$ $\"About$

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width -------xft\r
\n" ); document.write( "\n" ); document.write( "length 3x-7 ft\r
\n" ); document.write( "\n" ); document.write( "area = L * W\r
\n" ); document.write( "\n" ); document.write( "120 =x(3x-7)\r
\n" ); document.write( "\n" ); document.write( "120=3x^2-7x\r
\n" ); document.write( "\n" ); document.write( "3x^2-7x-120=0\r
\n" ); document.write( "\n" ); document.write( "use the formula method\r
\n" ); document.write( "\n" ); document.write( "a= 3 b= -7 c= -120
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 49 - -1440
\n" ); document.write( "b^2-4ac= 1489 $\"sqrt%28%091489++++%09%29\"$ = 38 3/5
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( "x1=( 7 + 38 3/5 )/ 6
\n" ); document.write( "x1= 7 3/5
\n" ); document.write( "x2=( 7 -38 3/5 ) / 6
\n" ); document.write( "x2= -5 1/4
\n" ); document.write( "Ignore negative value mph
\n" ); document.write( "x = 7 3/5 \r
\n" ); document.write( "\n" ); document.write( "width = 7 3/5\r
\n" ); document.write( "\n" ); document.write( "length =3*(38/5) -7
\n" ); document.write( "=15 4/5 feet\r
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