document.write( "Question 865120: Graph 3x+y <5 \n" ); document.write( "
Algebra.Com's Answer #521513 by jim_thompson5910(35256)\"\" \"About 
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To graph \"3x%2By+%3C+5\" we first need to graph \"3x%2By=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2By=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=5-3x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "This line has a slope of -3 and a y-intercept of 5. This is the point (0,5). Another point on this line is (1,2). You would start at (0,5) and go down 3 and over to the right 1 to get to (1,2)\r
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\n" ); document.write( "\n" ); document.write( "So plot (0,5) and (1,2). Draw a dashed line through these two points. This is the boundary of the shaded region and the dashed line means we are NOT including the boundary line in the solution set.\r
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\n" ); document.write( "\n" ); document.write( "If you were to solve \"3x%2By+%3C+5\" for y, you'd get \"y+%3C+-3x%2B5\" and you follow the same basic steps as shown above.\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality sign is a less than sign, we shade below the dashed line.\r
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\n" ); document.write( "\n" ); document.write( "To summarize, we have a dashed line and we are shading below the dashed line. This dashed line goes through (0,5) and (1,2)
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