document.write( "Question 865077: A hospital emergency room has collected a sample of n = 40 to estimate the mean number of visits per day. It has found the standard deviation is 32. Using a 90 percent confidence level, what is its margin of error? \n" ); document.write( "
Algebra.Com's Answer #521494 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Using this table, the critical value for the 90% confidence level is 1.645 (note: look in the row that starts with \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So z = 1.645\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given Information:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 40 \n" ); document.write( "s = 32\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Margin Of Error (ME)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the margin of error is approximately 8.32311480156\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Don't forget to round that if needed. According to the instructions posted that I see, there are no rounding instructions, but they may want you to round. \n" ); document.write( " |