document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72843>Question 72843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.A coin and a 1-6 number cube are tossed.Find P(heads and a prime number grater than 2)<BR>\n" );
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document.write( "2.Each letter of word DIVISIBILITY is writen on seperate card and the cards are placed in a bag.Then two cards are selected randomly without repacing the first card.Find P(letter I, letter I )\r<BR>\n" );
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document.write( "3.The sum of Sue's age and Sam's age is 35.The product of their ages is 300.<BR>\n" );
document.write( "If Sue is younger than Sam,how old is Sam.     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52147 by </B><A HREF=/tutors/aboutme.mpl?userid=blfaust><B>blfaust(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blfaust><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. The probability of heads is one-half Also 3 and 5 are the only primes between 1 and 6 that are greater than 2. So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F6 ALIGN=MIDDLE  ALT=\"2%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >equals<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > We want the Probability that both are going to happen so we multiply them together...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%2A%281%2F3%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29%2A%281%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=1/6 There is a one in six chance of this happening.<BR>\n" );
document.write( "2. The word \"DIVISIBILITY\" contains 11 letters and it has five \"I's\" in it. So the chance of the first card having an \"I\" is 5/11. Now that one card with an \"I\" is gone, because P stated you were going to pull an \"I\" followed by another \"I\", you only have four \"I's\" left and ten cards total. 4/10 reduced is 2/5 Multiply them together to find the P of both of them happening. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285%2F11%29%2A%282%2F5%29 ALIGN=MIDDLE  ALT=\"%285%2F11%29%2A%282%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >10/55 reduces to 2/11<BR>\n" );
document.write( "3. x+y=35 and x*y=300  Create a chart of numbers that add up to 35. Ex. 34+1...33+2...32+3...down to 18+17. You will see that there are only seventeen pairs of numbers to choose from. Now find a pair that gives you a product of 300. Soon you will see that 20*15+300. Since Sue is younger, Sam is 20. </SPAN>\n" );
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