document.write( "Question 72902: A radiator contains 6 quarts of a 25% antifreeze solution. How much antifreeze should be drained and replaced with pure antifreeze to yield a 33% solution? \n" ); document.write( "
Algebra.Com's Answer #52142 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 6*.25+X=.33(X+6) \n" ); document.write( "1.5+X=.33X+1.98 \n" ); document.write( "X-.33X=1.98-1.5 \n" ); document.write( ".67X=.48 \n" ); document.write( "X=.48/.67 \n" ); document.write( "X=.7164 QUARTS OF 100% ANTIFREEZE NEEDS TO BE ADDED TO GET TO A 33% MIXTURE. \n" ); document.write( "PROOF \n" ); document.write( "6*.25+.7164=.33(.7164+6) \n" ); document.write( "1.5+.7164=.33*6.7164 \n" ); document.write( "2.2164=2.2164 \n" ); document.write( " |