document.write( "Question 72902: A radiator contains 6 quarts of a 25% antifreeze solution. How much antifreeze should be drained and replaced with pure antifreeze to yield a 33% solution? \n" ); document.write( "
Algebra.Com's Answer #52142 by checkley75(3666)\"\" \"About 
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6*.25+X=.33(X+6)
\n" ); document.write( "1.5+X=.33X+1.98
\n" ); document.write( "X-.33X=1.98-1.5
\n" ); document.write( ".67X=.48
\n" ); document.write( "X=.48/.67
\n" ); document.write( "X=.7164 QUARTS OF 100% ANTIFREEZE NEEDS TO BE ADDED TO GET TO A 33% MIXTURE.
\n" ); document.write( "PROOF
\n" ); document.write( "6*.25+.7164=.33(.7164+6)
\n" ); document.write( "1.5+.7164=.33*6.7164
\n" ); document.write( "2.2164=2.2164
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