document.write( "Question 864972: $\"2x+%2B+4+%3E+4x+%2B+12\"$ \n" ); document.write( "

Algebra.Com's Answer #521405 by ben720(159) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2x+%2B+4+%3E+4x+%2B+12\"$
\n" ); document.write( "Subtract 2x from both sides
\n" ); document.write( " $\"4%3E2x%2B12\"$
\n" ); document.write( "Subtract 12 from both sides
\n" ); document.write( " $\"-8%3E2x\"$
\n" ); document.write( "Divide both sides by 2
\n" ); document.write( " $\"-4%3Ex\"$ , or $\"x%3C-4\"$ \n" ); document.write( "

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