document.write( "Question 851678: evaluate xy for x = 6 3/7 and y = 3 1/2 \n" ); document.write( "
Algebra.Com's Answer #521384 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
xy=
\n" ); document.write( "(6 3/7)(3 1/2)=
\n" ); document.write( "(45/7)(7/2)=
\n" ); document.write( "45/2
\n" ); document.write( "
\n" );