document.write( "Question 851678: evaluate xy for x = 6 3/7 and y = 3 1/2 \n" ); document.write( "
Algebra.Com's Answer #521384 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! xy= \n" ); document.write( "(6 3/7)(3 1/2)= \n" ); document.write( "(45/7)(7/2)= \n" ); document.write( "45/2 \n" ); document.write( " |