document.write( "Question 864899: A right triangle has a perimeter of 26 inches.The length of each side is increased to 7 times it original length. What is the perimeter of the larger triangle in inches? \n" ); document.write( "
Algebra.Com's Answer #521352 by jim_thompson5910(35256)\"\" \"About 
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Call the sides: s1, s2, s3\r
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\n" ); document.write( "\n" ); document.write( "The perimeter is P = s1 + s2 + s3\r
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\n" ); document.write( "\n" ); document.write( "The given perimeter is P = 26, so 26 = s1 + s2 + s3\r
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\n" ); document.write( "\n" ); document.write( "Each side s1, s2, s3 is \"increased to 7 times it original length\", so we have the new sides 7*s1, 7*s2, 7*s3. \r
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\n" ); document.write( "\n" ); document.write( "They add up to: 7*s1 + 7*s2 + 7*s3 = 7*(s1 + s2 + s3) = 7*P = 7*26 = 182\r
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\n" ); document.write( "\n" ); document.write( "So the new perimeter of the larger triangle is 182 inches
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