document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=864871>Question 864871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!<BR>\n" );
document.write( "Please help! On my worksheet it says to solve this question:<BR>\n" );
document.write( "logBasec(x-1)-logBasea(x+6)=logBasea(x-2)-logBasea(x+3)\r<BR>\n" );
document.write( "\n" );
document.write( "I'm not sure how to do this - also, how do I 'solve' if there are two variables? Could someone show me how to do this step-by-step? Thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #521331 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=521331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> logBasec(x-1)-logBasea(x+6)=logBasea(x-2)-logBasea(x+3) <BR>\n" );
document.write( "----------<BR>\n" );
document.write( "loga(x-1) - loga(x+6) = loga(x-2)-loga(x+3)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "(x-1)/(x+6) = (x-2)/(x+3)<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "(x-1)(x+3) = (x+6)(x-2)<BR>\n" );
document.write( "x^2 + 2x -3 = x^2 + 4x - 12<BR>\n" );
document.write( "----------------------------------<BR>\n" );
document.write( "2x-3 = 4x-12<BR>\n" );
document.write( "2x = 9<BR>\n" );
document.write( "x = 9/2<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------------ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );