document.write( "Question 864666: Can someone please help me figure out how to work this out:
\n" ); document.write( "Find the 0.99 confidence interval for .
\n" ); document.write( "In an effort to compare college costs in State of Michigan, a sample of 36 junior students is randomly selected statewide from the private colleges and 36 more from the public colleges. The private college sample resulted in a mean of $27,650 and the public college sample mean was $11,360.Assume the annual college fees for private colleges have a mounded distribution and the standard deviation is $1725. Find the 95% confidence interval for the mean costs for private colleges.\r
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Algebra.Com's Answer #521297 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In an effort to compare college costs in State of Michigan, a sample of 36 junior students is randomly selected statewide from the private colleges and 36 more from the public colleges. The private college sample resulted in a mean of $27,650 and the public college sample mean was $11,360.Assume the annual college fees for private colleges have a mounded distribution and the standard deviation is $1725. Find the 95% confidence interval for the mean costs for private colleges. \r
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\n" ); document.write( "sample mean:: 27,650
\n" ); document.write( "E = z*s/sqrt(n) = 1.96*1725/sqrt(36) = 563.5
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\n" ); document.write( "95%CI: 27,650-563.5 < u < 27650+563.5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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