document.write( "Question 864782: An investment of $500 at 8% per annum compounded annually grows to A$ in n years
\n" ); document.write( "a) solve this equation for n
\n" ); document.write( "b) so expressing n as a log function of A
\n" ); document.write( "calculate the value of n for each value of A 1) A = 1250 2) A = 350
\n" ); document.write( "c) graph the function in part a for 0\n" ); document.write( "d) state the domain and range\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out ? Thanks so much in advance:)
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Algebra.Com's Answer #521282 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
An investment of $500 at 8% per annum compounded annually grows to A$ in n years
\n" ); document.write( "Equation:: A = 500(1+0.08)^n
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\n" ); document.write( "a) solve this equation for n
\n" ); document.write( "1.08^n = A/500
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\n" ); document.write( "b) so expressing n as a log function of A
\n" ); document.write( "n*log(1.08) = log[A/500]
\n" ); document.write( "n = [log(A)-log(500)]/log(1.08)
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\n" ); document.write( "calculate the value of n for each value of A
\n" ); document.write( "1) A = 1250
\n" ); document.write( "n = [log(1250)-log(500)]/log(1.08) = 11.91
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\n" ); document.write( "2) A = 350
\n" ); document.write( "n = [log(350)-log(500)]/log(1.08) = -4.6345
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\n" ); document.write( "c) graph the function in part a for 0
\n" ); document.write( "Note: 0 is not a variable of that equation.
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\n" ); document.write( "d) state the domain and range
\n" ); document.write( "Domain: n is integer >= zero
\n" ); document.write( "Range: A is a Real Numbers >= 500
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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