document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72888>Question 72888</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1565771400/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The Speed boat could travel at 5 times the speed of the current. Thus, it could travel 300 miles downstream in 2 hours more than it took to travel 150 miles upriver.What was the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52128 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 300/(5C+C)=150/(5C-C)+2<BR>\n" );
document.write( "300/6C=150/4C+2<BR>\n" );
document.write( "50/C=150/4C+2<BR>\n" );
document.write( "50/C=(150+8C)/4C<BR>\n" );
document.write( "C(150+8C)=50*4C<BR>\n" );
document.write( "150C+8C^2=200C<BR>\n" );
document.write( "8C^2+150C-200C=0<BR>\n" );
document.write( "8C^2-50C=0<BR>\n" );
document.write( "C(8C-50)=0<BR>\n" );
document.write( "C=0<BR>\n" );
document.write( "8C-50=0<BR>\n" );
document.write( "8C=50<BR>\n" );
document.write( "C=50/8<BR>\n" );
document.write( "C=6.25 MPH FOR THE CURRENT SPEED<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "300/6*6.25=150/4*6.25 +2<BR>\n" );
document.write( "300/37.5=150/25+2<BR>\n" );
document.write( "8=6+2<BR>\n" );
document.write( "8=8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );