document.write( "Question 864753: I need to find the foci and the vertices of this hyperbola [(y+2)^2]/4-[x^2]/12=1
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Algebra.Com's Answer #521253 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Standard Form of an Equation of an Hyperbola opening up and down is:
\n" ); document.write( " \"%28y-k%29%5E2%2Fb%5E2+-+%28x-h%29%5E2%2Fa%5E2+=+1\" with C(h,k) and vertices 'b' units up and down from center
\n" ); document.write( "Foci \"sqrt%28a%5E2%2Bb%5E2%29\"units units up and down from center, along x = h
\n" ); document.write( "\"%28y%2B2%29%5E2%2F2%5E2+-x%5E2%2F12=1+\" C(0,-2)
\n" ); document.write( "Vertices (0,0) and (0,-4)
\n" ); document.write( "Foci: sqrt(16) = 4 units Up and down from Center (0, 2) and (0,-6)
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