document.write( "Question 864732: In a company that designs pollution control equipment, the equation $\"d=k%5E3+-8k%5E2+%2B26k+%2B1\"$ where d is the number of thousands of dollars per month and k is the number of millions of kilowatt hours per month used in the business:\r
\n" ); document.write( "\n" ); document.write( "a) find the cost of 1.5 million kwh - I got 25.38 thousand
\n" ); document.write( "b) According to the model, how much would you pay if no electricity were used in a given month and why? -I got 1 (thousand) +1 is a constant in the equation\r
\n" ); document.write( "\n" ); document.write( "c) how much electricity can be used without the bill exceeding $35 000 per month? I got 2.6 (million kwh) I'm not sure if this is right.\r
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Algebra.Com's Answer #521248 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "a)Yes, 25.38 thousand 0r = $25,380
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document.write( "b)Yes, $1000
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document.write( "c)Using graphing calculator, 3.22 million kwh
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document.write( " k = 3.22 ⇒  d = 35 \n" );
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