document.write( "Question 864679: when the price of a box of peanuts is increased by 30% its sales decreased by x% such that the revenue decreased by 9%.what is the value of x?
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Algebra.Com's Answer #521192 by josgarithmetic(39627)\"\" \"About 
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Idea applied is \"Price%2AItemCount=Revenue\".
\n" ); document.write( "Let p = original price
\n" ); document.write( "Let q = original count of items sold
\n" ); document.write( "x/100 = the fraction of q not sold, compared to q.\r
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\n" ); document.write( "\n" ); document.write( "Price____________Item Count__________Revenue
\n" ); document.write( "p________________q___________________pq
\n" ); document.write( "p(1.30)__________\"q-q%28x%2F100%29\"__________\"p%281.30%29%28q-q%28x%2F100%29%29=pq%281.30%29%281-x%2F100%29\"\r
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\n" ); document.write( "\n" ); document.write( "Revenue decreased by 9% upon the price increase.
\n" ); document.write( "Also meaning, new revenue became 91% of original revenue, since 9+91=100.
\n" ); document.write( "\"highlight%28pq%281.30%29%281-x%2F100%29=pq%2891%2F100%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1.30%281-x%2F100%29=91%2F100\" Divided both members by pq.
\n" ); document.write( "\"1.3-%281.3%2F100%29x=91%2F100\"
\n" ); document.write( "\"130-1.3x=91\"
\n" ); document.write( "\"130-91=1.3x\"
\n" ); document.write( "\"1.3x=39\"
\n" ); document.write( "\"x=%283%2A13%29%2F%2813%2A0.1%29\"
\n" ); document.write( "\"highlight%28x=30%29\"
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\n" ); document.write( "The percent drop in count of items sold was 30.
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