document.write( "Question 72830: by using subsitution of linear systems how do you figure out this problem? \r
\n" ); document.write( "\n" ); document.write( " x+y=4
\n" ); document.write( " -5+2y=-6
\n" ); document.write( "
\n" ); document.write( " PLEASE HELP CUZ IM NOT UNDERSTANING THIS
\n" ); document.write( "

Algebra.Com's Answer #52118 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Solve one of the equations for a single variable (I'm going to solve for y on the top). You then plug this y value into any y you see into the 2nd equation
\n" ); document.write( "\"y=4-x\"Solve for y
\n" ); document.write( "\"-5%2B2%284-x%29=-6\"Now you can solve for x
\n" ); document.write( "\"-5%2B8-2x=-6\"
\n" ); document.write( "\"-2x=-9\"
\n" ); document.write( "\"x=9%2F2\"
\n" ); document.write( "Now plug this into x+y=4
\n" ); document.write( "\"9%2F2%2By=4\"Solve for y
\n" ); document.write( "\"y=4-9%2F2\"
\n" ); document.write( "\"y=%288-9%29%2F2\"
\n" ); document.write( "\"y=-1%2F2\"
\n" ); document.write( "So the solution is (9/2,-1/2) or (4.5,-0.5). In a nutshell you are substituting to eliminate one variable. This allows you to work with one variable, since you cannot simultaneously solve for 2 variables. You then take the answer of one and plug it in the other equation. Hope this helps.
\n" ); document.write( "
\n" );