document.write( "Question 864655: Solve each inequality. graph its solution, and write the solution in set notation.
\n" ); document.write( "|x+7|+15>12\r
\n" ); document.write( "\n" ); document.write( "Here's what I did:
\n" ); document.write( "1)|x+7|+15>12
\n" ); document.write( " -15 -15\r
\n" ); document.write( "\n" ); document.write( "2)|x+7|>-3\r
\n" ); document.write( "\n" ); document.write( "3) x+7<-3 or x+7>3\r
\n" ); document.write( "\n" ); document.write( "4) x+7<-3 or x+7>3
\n" ); document.write( " -7 -7 -7 -7\r
\n" ); document.write( "\n" ); document.write( "5)x<-10 or x>-4\r
\n" ); document.write( "\n" ); document.write( "answer: (-infinity,-10)U(-4,infinity)\r
\n" ); document.write( "\n" ); document.write( "Im not sure if this is right. I think it is either no solution, or (-infinity,infinity)
\n" ); document.write( "Thanks!!!\r
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Algebra.Com's Answer #521161 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
|x+7|+15 > 12 \r
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\n" ); document.write( "\n" ); document.write( "|x+7|+15-15 > 12-15 \r
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\n" ); document.write( "\n" ); document.write( "|x+7| > -3 \r
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\n" ); document.write( "\n" ); document.write( "Since |x+7| is never negative, it is always greater than -3 for any value of x\r
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\n" ); document.write( "\n" ); document.write( "So |x+7| > -3 is true for all values of x making the answer in interval notation to be (-infinity, infinity)
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