document.write( "Question 864578: find three consecutive odd integers such that twice the sum of the first two 11 is more than three times greater \n" ); document.write( "
Algebra.Com's Answer #521154 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the numbers be x , x+2, x+4\r \n" ); document.write( "\n" ); document.write( "twice the sum of first two\r \n" ); document.write( "\n" ); document.write( "2(x+x+2) \n" ); document.write( "2(2x+2)=3(x+4)+11\r \n" ); document.write( "\n" ); document.write( "4x+4=3x+12+11\r \n" ); document.write( "\n" ); document.write( "4x+4=3x+23\r \n" ); document.write( "\n" ); document.write( "4x-3x=23-4\r \n" ); document.write( "\n" ); document.write( "x=19\r \n" ); document.write( "\n" ); document.write( "19,21,23 \n" ); document.write( " |