document.write( "Question 72883: Use log5(2)~.4307 and log5(3)~.6826 to approximate the expression without a calculator:
\n" ); document.write( "log5(18)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #52114 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use these identities to solve\r
\n" ); document.write( "\n" ); document.write( " \"ylog%28x%29=log%28x%29%5Ey\"
\n" ); document.write( " \"log%28x%29%2Blog%28y%29=log%28x%2Ay%29\"\r
\n" ); document.write( "\n" ); document.write( "If we let x=2 and y=3 for the 1st identity we get\r
\n" ); document.write( "\n" ); document.write( "\"2%2Alog_%5B5%5D%283%29=log_%5B5%5D%283%5E2%29=log_%5B5%5D%289%29\"This gets us halfway to 18.
\n" ); document.write( "\"2%2Alog_%5B5%5D%283%29=2%2A%280.6826%29=1.3652\"Now plug in the approximate values
\n" ); document.write( "\"log_%5B5%5D%282%29%2Blog_%5B5%5D%289%29=log_%5B5%5D%282%2A9%29=log_%5B5%5D%2818%29\"Notice how this turns into log(18) using the identities.
\n" ); document.write( "\"0.4307%2B1.3652=1.7959\"Plug in remaining values.
\n" ); document.write( "Check:
\n" ); document.write( "\"5%5E1.7959=18.00032\"It's close enough to work
\n" ); document.write( "So \"log_%5B5%5D%2818%29=1.7959\"Approximately of course
\n" ); document.write( "
\n" );