document.write( "Question 72856: Simplify: (6-a/b)/24/b\r
\n" ); document.write( "\n" ); document.write( "I am a little confussed and was hoping you could help me. I came up with this answer: \"%28-a%2B6b%29%2F%2824b%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "The question I have is now with this anwer do I now cancel out the b's to make the answer \"%286-a%29%2F24\". This is where I am stuck. Please help. Thanks
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Algebra.Com's Answer #52113 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
(6-A/B/(24/B) NOW INVERT THE DENOMINATOR & MULTIPLY
\n" ); document.write( "(6-A/B)(B/24) NOW MULTIPLY EACH TERM IN THR FIRST () BY THE SECOND TERM(B/24)
\n" ); document.write( "6*(B/24)-AB^2/24B
\n" ); document.write( "6B/24-AB/24 NOW COMBINE THESE TWO TERMS
\n" ); document.write( "(6B-AB)/24
\n" ); document.write( "B(6-A)/24
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