document.write( "Question 72862: SIMPLIFY\r
\n" ); document.write( "\n" ); document.write( "1. 5x^3/(5x)^3\r
\n" ); document.write( "\n" ); document.write( "2. (7t^3/21t)^3\r
\n" ); document.write( "\n" ); document.write( "3. (2k^3/3k^-2)^-2 \n" ); document.write( "
Algebra.Com's Answer #52111 by jmg(22)\"\" \"About 
You can put this solution on YOUR website!
1. Solve the bottom first so that you have 5x^3/125x^3. Then you just cancel out the x^3 and simplify 5/125 to 1/25.\r
\n" ); document.write( "\n" ); document.write( "2. Simplify inside the parentheses first. 7/21 would reduce to 1/3. The t on the bottom will cancel out with one on the top and leave you with
\n" ); document.write( "(t^2/3)^3. Then raise everything to the 3rd power. (t^2)^3 = t^6, 3^3= 27.
\n" ); document.write( "Giving the solution t^6/27\r
\n" ); document.write( "\n" ); document.write( "3. you cannot reduce 2/3 so you solve the k. When the variables are being divided you subtract the exponents. So 3 - (- 2) = 5\r
\n" ); document.write( "\n" ); document.write( "So you get (2k^5/3)^-2. When the exponent is negative you flip the fraction and change the exponent to a positive (you also could have done this in the previous step with the k^-2, but I thought it was easier to explain this way)\r
\n" ); document.write( "\n" ); document.write( "So you have (3/2k^5)^2\r
\n" ); document.write( "\n" ); document.write( "Square everything in the fraction.
\n" ); document.write( "9/4k^10\r
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