document.write( "Question 864539: part of the proceeds from a garage sale was $610 worth of $10 and $20 bills.if there are 7 more $10 bills than $20 bills, how many $10 and $20 bills were there each? \n" ); document.write( "
Algebra.Com's Answer #521098 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! LET X BE THE NUMBER OF $20 BILLS \n" ); document.write( "LET X+7 BE THE NUMBER OF $10 BILLS. \n" ); document.write( "20X+10(X+7)=610 \n" ); document.write( "20X+10X+70=310 \n" ); document.write( "30X=310-70 \n" ); document.write( "30X=240 \n" ); document.write( "X=240/30 \n" ); document.write( "X=8 $20 BILLS. \n" ); document.write( "8+7=15 $ 10 BILLS. \n" ); document.write( "PROOFS: \n" ); document.write( "20*8+15*10=310 \n" ); document.write( "160+150=310 \n" ); document.write( "310=310 \n" ); document.write( " |