document.write( "Question 72863This question is from textbook algerbra 1
\n" );
document.write( ": -5x-8y=15(-3,0)
\n" );
document.write( "this is what i got so far\r
\n" );
document.write( "\n" );
document.write( "-5x
\n" );
document.write( "5(cancel out)8=15
\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #52106 by checkley75(3666) ![]() You can put this solution on YOUR website! -5X-8Y=15 \n" ); document.write( "-8Y=5X+15 \n" ); document.write( "Y=5X/-8+15/-8 \n" ); document.write( "Y=-5X/8-15/8 IF THIS IS THE LINE FORMULA & IT HAS A SLOPE (m) OF (-5/8) GOES THROUGH (-3,0) THEN WE NEED TO SOLVE FOR THE Y INTERCEPT (b) IN THE LINE FORMULA Y=mX+b BY REPLACING THE X & Y TERMS BY (-3,0) \n" ); document.write( "0=-5/8*-3+b \n" ); document.write( "0=15/8+b \n" ); document.write( "b=-15/8 THUS THE FORMULA IS \n" ); document.write( "Y=-5X/8-15/8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |