document.write( "Question 9536: Ann's age this year is a multiple of 7. Next year her age will be a multiple of 4. Her age is between 10 and 60. Hoe old is Ann \n" ); document.write( "
Algebra.Com's Answer #5210 by mathmaven53(29)![]() ![]() ![]() You can put this solution on YOUR website! Let A be her age this year then A = 7k for some positive integer k\r \n" ); document.write( "\n" ); document.write( " A+1 is her age next year and A+1 = 4l for some positive integer l\r \n" ); document.write( "\n" ); document.write( " 1 = A+1 -A\r \n" ); document.write( "\n" ); document.write( " = 4l - 7k\r \n" ); document.write( "\n" ); document.write( " We have to solve 4l - 7k = 1 in positive integers\r \n" ); document.write( "\n" ); document.write( " We write equivalently 4l -8k + k = 1\r \n" ); document.write( "\n" ); document.write( " 4l - 8k = 1 -k\r \n" ); document.write( "\n" ); document.write( " Let 1-k = 4r for some integer r\r \n" ); document.write( "\n" ); document.write( " Then k = 1 -4r\r \n" ); document.write( "\n" ); document.write( " Substitute for k and solve for l in 4l - 7k = 1\r \n" ); document.write( "\n" ); document.write( " We get l = 2-7r\r \n" ); document.write( "\n" ); document.write( " A = 7k \n" ); document.write( " = 7 -28r\r \n" ); document.write( "\n" ); document.write( " 10 < A < 60\r \n" ); document.write( "\n" ); document.write( " By substituting for A and solving for r we get\r \n" ); document.write( "\n" ); document.write( " -53/28 < r < -3/28\r \n" ); document.write( "\n" ); document.write( " The only integer that satisfies this is r=-1\r \n" ); document.write( "\n" ); document.write( " Then A = 7-28r \r \n" ); document.write( "\n" ); document.write( " = 35\r \n" ); document.write( "\n" ); document.write( " Ann is 35 this year which is a multiple of 7 \n" ); document.write( "next year she is 36 which is a multiple of 4\r \n" ); document.write( "\n" ); document.write( " and 35 is between 10 and 60 \n" ); document.write( " \n" ); document.write( " |