document.write( "Question 864414: Use the given information to find each value\r
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document.write( "cos t = 5/13 , 0 < t < pi/2\r
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document.write( "cos 2t=\r
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document.write( "sin 2t =\r
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document.write( "cos t/2 = \r
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document.write( "sin t/2 = \n" );
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Algebra.Com's Answer #520986 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Use the given information to find each value \n" ); document.write( "cos t = 5/13 , 0 < t < pi/2 \n" ); document.write( "cos 2t= \n" ); document.write( "sin 2t = \n" ); document.write( "cos t/2 = \n" ); document.write( "sin t/2 = \n" ); document.write( "*** \n" ); document.write( "You are working with a (5-12-13) reference right triangle in quadrant I. \n" ); document.write( "sin t =12/13 \n" ); document.write( "cos 2t=cos^2t-sin^2t=25/169-144/169=-119/169 \n" ); document.write( "sin 2t=2sin t*cos t=2*12/13*5/13=120/169 \n" ); document.write( " \n" ); document.write( " |