document.write( "Question 864318: Fidn three consecutive odd integers such that the sum of all three is 42 less than the product of the larger two. \n" ); document.write( "
Algebra.Com's Answer #520931 by mananth(16946) You can put this solution on YOUR website! let the integers be x x+2 & x+4\r \n" ); document.write( "\n" ); document.write( "x+x+2+x+4 = (x+2)(x+4)-42\r \n" ); document.write( "\n" ); document.write( "3x+6=x^2+6x+8-42\r \n" ); document.write( "\n" ); document.write( "3x+6 =x^2+6x-40\r \n" ); document.write( "\n" ); document.write( "x^2+3x-40=0\r \n" ); document.write( "\n" ); document.write( "x^2+8x-5x-40=0\r \n" ); document.write( "\n" ); document.write( "x(x+8)-5(x+8)=0\r \n" ); document.write( "\n" ); document.write( "(x+8)(x-5)=0\r \n" ); document.write( "\n" ); document.write( "x=-8 OR x=5\r \n" ); document.write( "\n" ); document.write( "but odd integer \n" ); document.write( "so, x=5 \n" ); document.write( "5,7,9 \n" ); document.write( " \n" ); document.write( " |