document.write( "Question 864342: So, we started learning about systems of equations, and I'm a bit tripped up.\r
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document.write( "{4X+2Y=6
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document.write( "{-3X-7Y=1 \r
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document.write( "Using substitution how would I solve this system?\r
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document.write( "Another one that has me confused is this:\r
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document.write( "{X+Y=13
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document.write( "{X-Y=2\r
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document.write( "I have tried it a couple times before, but I'm quite sure they aren't correct. \n" );
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Algebra.Com's Answer #520927 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 4x+2y=6 \n" ); document.write( "/2 \n" ); document.write( "we get 2x+y=3\r \n" ); document.write( "\n" ); document.write( "2 x + y = 3 .............1 \n" ); document.write( " y = 3 + -2 x \n" ); document.write( " \n" ); document.write( " y = 3 -2 x \n" ); document.write( "-3 x -7 y = 1 .....................2 \n" ); document.write( "Substitute y in (2) \n" ); document.write( "-3 x -7 ( 3 -2 x ) = 1 \n" ); document.write( "-3 x -21 + 14 x = 1 \n" ); document.write( "-3 x 14 x = 22 \n" ); document.write( "11 x = 22 \n" ); document.write( "/ 11 \n" ); document.write( "x= 2 \n" ); document.write( "Plug the value of x in (1) \n" ); document.write( "2 x + y = 3 \n" ); document.write( "2 * 2 + 1 y = 3 \n" ); document.write( "4 + 1 y = 3 \n" ); document.write( " y = -1 \n" ); document.write( "/ 1 \n" ); document.write( "y= -1 \n" ); document.write( "--------------\r \n" ); document.write( "\n" ); document.write( "x+y=13 \n" ); document.write( "x-y=2 \n" ); document.write( "in the second equation \n" ); document.write( "y=x-2substitute y in (1)\r \n" ); document.write( "\n" ); document.write( "x+(x-2)=13\r \n" ); document.write( "\n" ); document.write( "2x-2=13 \n" ); document.write( "2x=15 \n" ); document.write( "x=15/2\r \n" ); document.write( "\n" ); document.write( "Plug x in (2)\r \n" ); document.write( "\n" ); document.write( "x-y=2 \n" ); document.write( "(15/2)-y=2\r \n" ); document.write( "\n" ); document.write( "y= 15/2 -2\r \n" ); document.write( "\n" ); document.write( "y=11/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |