document.write( "Question 72804: solve LOGa(8x+5) =LOGa(4x+29)\r
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document.write( "the a is lower than the word LOG. What does this mean?\r
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document.write( "Someone pleeze help \n" );
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Algebra.Com's Answer #52090 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! solve LOGa(8x+5) =LOGa(4x+29) \n" ); document.write( "the a is lower than the word LOG. What does this mean? \n" ); document.write( "a is the base of the log, if it is not specified it is assumed to be 10 \n" ); document.write( ": \n" ); document.write( "However, it really doesn't matter what the value of \"a\" is because; \n" ); document.write( ": \n" ); document.write( "If loga(8x+5) equals loga(4x+29), \n" ); document.write( "then, \n" ); document.write( "(8x+5) = (4x+29) \n" ); document.write( ": \n" ); document.write( "easy to solve \n" ); document.write( "8x + 5 = 4x + 29 \n" ); document.write( "8x - 4x = 29 - 5 \n" ); document.write( "4x = 24 \n" ); document.write( "x = 24/4 \n" ); document.write( "x = 6 \n" ); document.write( ": \n" ); document.write( "You can substitute 6 for x in the original equation and see: \n" ); document.write( "loga(8(6)+5) = loga(4(6)+29) \n" ); document.write( "loga(48+5) - loga(24+29) \n" ); document.write( "loga(53) = loga(53) \n" ); document.write( " |