document.write( "Question 72804: solve LOGa(8x+5) =LOGa(4x+29)\r
\n" ); document.write( "\n" ); document.write( "the a is lower than the word LOG. What does this mean?\r
\n" ); document.write( "\n" ); document.write( "Someone pleeze help
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Algebra.Com's Answer #52090 by ankor@dixie-net.com(22740)\"\" \"About 
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solve LOGa(8x+5) =LOGa(4x+29)
\n" ); document.write( "the a is lower than the word LOG. What does this mean?
\n" ); document.write( "a is the base of the log, if it is not specified it is assumed to be 10
\n" ); document.write( ":
\n" ); document.write( "However, it really doesn't matter what the value of \"a\" is because;
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\n" ); document.write( "If loga(8x+5) equals loga(4x+29),
\n" ); document.write( "then,
\n" ); document.write( "(8x+5) = (4x+29)
\n" ); document.write( ":
\n" ); document.write( "easy to solve
\n" ); document.write( "8x + 5 = 4x + 29
\n" ); document.write( "8x - 4x = 29 - 5
\n" ); document.write( "4x = 24
\n" ); document.write( "x = 24/4
\n" ); document.write( "x = 6
\n" ); document.write( ":
\n" ); document.write( "You can substitute 6 for x in the original equation and see:
\n" ); document.write( "loga(8(6)+5) = loga(4(6)+29)
\n" ); document.write( "loga(48+5) - loga(24+29)
\n" ); document.write( "loga(53) = loga(53)
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