document.write( "Question 864286: Joe can cut and split a cord of firewood in 9 fewer hr(s) than Suzie can. When they work together, it takes them 6 hour(s). How long would it take each of themm to do the same job alone? \n" ); document.write( "
Algebra.Com's Answer #520895 by lwsshak3(11628)\"\" \"About 
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Joe can cut and split a cord of firewood in 9 fewer hr(s) than Suzie can. When they work together, it takes them 6 hour(s). How long would it take each of them to do the same job alone?
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\n" ); document.write( "let x=hours Suzie can finish the job alone
\n" ); document.write( "1/x=her work rate
\n" ); document.write( "x-9=hours Joe can finish the job alone
\n" ); document.write( "1/(x-9)=his work rate
\n" ); document.write( "1/6=work rate of Joe and Suzie working together
\n" ); document.write( "...
\n" ); document.write( "sum of individual work rates equal work rate working together
\n" ); document.write( "\"1%2Fx%2B1%2F%28x-9%29=1%2F6\"
\n" ); document.write( "LCD:6x(x-9)
\n" ); document.write( "6(x-9)+6x=x(x-9)
\n" ); document.write( "6x-54+6x=x^2-9x
\n" ); document.write( "x^2-21x+54=0
\n" ); document.write( "(x-18)(x-3)=0
\n" ); document.write( "x=3(reject, not reasonable)
\n" ); document.write( "or
\n" ); document.write( "x=18
\n" ); document.write( "x-9=9
\n" ); document.write( "hours Suzie can finish the job alone=18
\n" ); document.write( "hours Joe can finish the job alone=9 \n" ); document.write( "
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