document.write( "Question 864243: Suppose 8 pints of a 13% alcohol solution is mixed with 2 pints of a 60% alcohol solution. What is the concentration of alcohol in the new 10 pint mixture? \n" ); document.write( "
Algebra.Com's Answer #520854 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .13*8+.60*2=10x \n" ); document.write( "1.04+1.2=10x \n" ); document.write( "2.24=10x \n" ); document.write( "x=2.24/10 \n" ); document.write( "x=.224% mixture. \n" ); document.write( " |