document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=9449>Question 9449</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello-<BR>\n" );
document.write( "Thanks in advance for helping me with this problem.  I found the answer, but through guess and check, so it would be very helpful if you could tell me how to find the answer mathematicaly.\r<BR>\n" );
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document.write( "Mark and David both own a lot of Matchbox cars.  Mark owns seven times the square root of the amount David owns.  Together they own the square root of 9 multiplyed be the quotient of 27,150 and 181.  How many cars do they own in all?  How many cars does each boy own?  Who owns more?\r<BR>\n" );
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document.write( "This really stumped me, but I found an answer.\r<BR>\n" );
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document.write( "Mark owns 126 cars.<BR>\n" );
document.write( "David owns 324 cars.<BR>\n" );
document.write( "Together they own 450 cars.<BR>\n" );
document.write( "David owns more.\r<BR>\n" );
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document.write( "Thanks again in advance and I can't wait to hear from you.\r<BR>\n" );
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document.write( "Sincerely,<BR>\n" );
document.write( "Trevor Pierce </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5208 by </B><A HREF=/tutors/aboutme.mpl?userid=mathmaven53><B>mathmaven53(29)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathmaven53><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let m be number of cars owned by Mark\r<BR>\n" );
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document.write( "    d be number owned by David\r<BR>\n" );
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document.write( " m = 7 sqrt d\r<BR>\n" );
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document.write( "m + d = (sqrt 9)(27150/181)\r<BR>\n" );
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document.write( "   The right side is computed to be 450\r<BR>\n" );
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document.write( " Then  7 sqrt d + d = 450\r<BR>\n" );
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document.write( "   (sqrt d)^2 + 7 sqrt d - 450 = 0\r<BR>\n" );
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document.write( "by quadratic formula \r<BR>\n" );
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document.write( "sqrt d = [-7 + sqrt(49 +4(450))]/2\r<BR>\n" );
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document.write( " We use the positve square root in answer  else m would be a negative number<BR>\n" );
document.write( "Simplifying gives \r<BR>\n" );
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document.write( " sqrt d = 18\r<BR>\n" );
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document.write( " d = 324\r<BR>\n" );
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document.write( " m = 7 sqrt d\r<BR>\n" );
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document.write( "   = 126\r<BR>\n" );
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document.write( " I used a calculator to get these intermediate answers \r<BR>\n" );
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document.write( " David has 324 cars and Mark has 126<BR>\n" );
document.write( " David has more cars.<BR>\n" );
document.write( " </SPAN>\n" );
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