document.write( "Question 72831: Please help me solve this $\"-2t%5E2+-+5t+%2B+12+=+0\"$ \r
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Algebra.Com's Answer #52079 by checkley75(3666) $\"\"$ $\"About$

You can put this solution on YOUR website!
-2T^2-5T+12=0
\n" ); document.write( "(2T-3)(-T-4)=0
\n" ); document.write( "2T-3=0
\n" ); document.write( "2T=3
\n" ); document.write( "T=3/2 ANSWER.
\n" ); document.write( "-T-4=0
\n" ); document.write( "T=4/-1
\n" ); document.write( "T=-4 ANSWER. \n" ); document.write( "

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