document.write( "Question 864069: The Bureau of Labor Statistics’ American Time Use Survey showed that the amount of time spent using a computer for leisure varied greatly by age. Individuals age 75 and over averaged .40 hour (24 minutes) per day using a computer for leisure. Individuals ages 15 to 19 spend 1.3 hour per day using a computer for leisure. If these times follow an exponential distribution, find the proportion of each group that spends:\r
\n" ); document.write( "\n" ); document.write( "(a)Less than 21 minutes per day using a computer for leisure. (Round your answers to 4 decimal \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(b)More than two hours. (Round your answers to 4 decimal places.)\r
\n" ); document.write( "\n" ); document.write( "(c)Between 42 minutes and 126 minutes using a computer for leisure. (Round your answers to 4 decimal places.)
\n" ); document.write( "
\n" ); document.write( " (d)Find the 28th percentile. Seventy two percent spend more than what amount of time? (Round your answers to 2 decimal places.)
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #520756 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "POISSON 1.3 hr = 78 min
\n" ); document.write( "a) ≥ 75 P(x<21) = 24.26%
\n" ); document.write( " 15-19 P(x<21) = 0%
\n" ); document.write( "b) ≥ 75 P(x>120) = 0
\n" ); document.write( " 15-19 P(x>120 ) = 0
\n" ); document.write( "c) P( 42 ≤ x ≤ 126) = P(x ≤ 126) - P( x ≤ 42)
\n" ); document.write( " poissoncdf(24, 126) - poisssoncdf(24,42) = 1 - .9997 = .0003
\n" ); document.write( "etc
\n" ); document.write( "d) X = poissinv(P,lambda) = poissinv(.28, 24)
\n" ); document.write( " X = poissinv(P,lambda) = poissinv(.28, 78) \n" ); document.write( "
\n" );