document.write( "Question 863979: You need a 95% alcohol solution. On hand, you have a 60 mL of a 25% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?
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Algebra.Com's Answer #520708 by mananth(16946) $\"\"$ $\"About$

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--- percent ---------------- Amount
\n" ); document.write( "Alcohol I 25 ---------------- 60 ml
\n" ); document.write( "Pure alcohol 100 ---------------- x ml
\n" ); document.write( "Mixture 95 ---------------- 60 + x ml
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\n" ); document.write( "25 * 60 + 100 x = 95 ( 60 + x )
\n" ); document.write( "1500 + 100 x = 5700 + 95 x
\n" ); document.write( "100 x -95 x = -1500 + 5700
\n" ); document.write( "5 x = 4200
\n" ); document.write( "/ 5
\n" ); document.write( "x = 840 ml Pure alcohol
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\n" ); document.write( "m.ananth@hotmail.ca
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