document.write( "Question 863955: how do you solve ln(x) -ln(x-1)=2 \n" ); document.write( "

Algebra.Com's Answer #520699 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln%28x%29+-ln%28x-1%29=2\"$
\n" ); document.write( " $\"ln%28x%2F%28x-1%29%29=2\"$
\n" ); document.write( " $\"x%2F%28x-1%29=e%5E2\"$
\n" ); document.write( " $\"x=e%5E2%28x-1%29\"$
\n" ); document.write( " $\"x=e%5E2x-e%5E2\"$
\n" ); document.write( " $\"x-e%5E2x=-e%5E2\"$
\n" ); document.write( " $\"x%281-e%5E2%29=-e%5E2\"$
\n" ); document.write( " $\"x=-e%5E2%2F%281-e%5E2%29\"$
\n" ); document.write( " $\"x=e%5E2%2F%28e%5E2-1%29\"$
\n" ); document.write( " \n" ); document.write( "

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