document.write( "Question 863896: Write a system of equations to model the problem and solve. Please show all work
\n" ); document.write( "Theo flies from Atlanta to San Francisco. It takes 5.6 hours to travel 2100 miles against the head wind. At the same time, Della flies from San Francisco to Atlanta. Her plane travels with the same avergae air speed. but with the tail wind. it only takes her 4.8 hours. Find the air speed and the wind speed.
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Algebra.Com's Answer #520689 by mananth(16946)\"\" \"About 
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Plane speed =x mph (both speeds are same)
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 5.6 hours
\n" ); document.write( "with wind 4 hours
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\n" ); document.write( "Distance against 2100 miles distance with 2100 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "2100.00 / ( x - y )= 5.60
\n" ); document.write( "5.60 ( x - y ) = 4.00
\n" ); document.write( "5.60 x - 5.60 y = 2100.00 ....................1
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\n" ); document.write( "2100.00 / ( x + y )= 4.00
\n" ); document.write( "4.00 ( x + y ) = 2100.00
\n" ); document.write( "4.00 x + 4.00 y = 2100.00 ...............2
\n" ); document.write( "Multiply (1) by 4.00
\n" ); document.write( "Multiply (2) by 5.60
\n" ); document.write( "we get
\n" ); document.write( "22.40 x + -22.40 y = 8400.00
\n" ); document.write( "22.40 x + 22.40 y = 11760.00
\n" ); document.write( "44.80 x = 20160.00
\n" ); document.write( "/ 44.80
\n" ); document.write( "x = 450.00 mph
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\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "5.60 x -5.60 y = 2100.00
\n" ); document.write( "2520.00 -5.60 -2520.00 = 2100.00
\n" ); document.write( "-5.60 y = 2100.00
\n" ); document.write( "-5.60 y = -420.00 mph
\n" ); document.write( " y = 75.00
\n" ); document.write( "Plane speed 450.00 mph
\n" ); document.write( "wind speed 75.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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