document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72791>Question 72791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangle is 18 ft and the width is 6 ft, find its length.  [Hint: The perimeter of a rectangle is given by P = 2L + 2W.]<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52063 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Starting with the formula for the perimeter of a rectangle: <BR>\n" );
document.write( "P = 2L+2W and given that P = 18, W = 6, substitute these into the formula and solve for L<BR>\n" );
document.write( "18 = 2L+2(6)<BR>\n" );
document.write( "18 = 2L+12 Subtract 12 from both sides.<BR>\n" );
document.write( "18-12 = 2L<BR>\n" );
document.write( "6 = 2L Divide both sides by 2.<BR>\n" );
document.write( "6/2 = 2L/2 Simplify.<BR>\n" );
document.write( "3 = L or L = 3 </SPAN>\n" );
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