document.write( "Question 9517: In a mixture of concrete, there are 3 lb of cement mix for each pound of gravel. If the mixture contains a total of 140 lbs of these two ingredients, how many pounds of gravel are there? \n" ); document.write( "
Algebra.Com's Answer #5206 by DWL(56)\"\" \"About 
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Let:\r
\n" ); document.write( "\n" ); document.write( "x = Cement
\n" ); document.write( "y = Gravel\r
\n" ); document.write( "\n" ); document.write( "x + y =140\r
\n" ); document.write( "\n" ); document.write( "We also know that the cement is 3 times as much as the gravel, so:\r
\n" ); document.write( "\n" ); document.write( "x = 3y\r
\n" ); document.write( "\n" ); document.write( "So now substitute in the equation x + y = 140 and it becomes: \"3y%2By=140\"\r
\n" ); document.write( "\n" ); document.write( "Combine Terms\r
\n" ); document.write( "\n" ); document.write( "\"4y=140\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 4\r
\n" ); document.write( "\n" ); document.write( "\"y=35\"\r
\n" ); document.write( "\n" ); document.write( "so the Gravel weighs 35 pounds. We know there is 3 pounds of cement for every pound of gravel, so\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2A35=105\"\r
\n" ); document.write( "\n" ); document.write( "so the cement = 105.\r
\n" ); document.write( "\n" ); document.write( "Answer\"\r
\n" ); document.write( "\n" ); document.write( "35 Lbs. of Gravel
\n" ); document.write( "105 Lbs. of Cement
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