document.write( "Question 115576: I am very frustrated! I am doing a piece of coursework and have discovered a changing difference pattern. Could someone please explain to me how to apply it and simplify it for my own results. I know the algebraic expression for a changing difference sequence is: a + (n-1)d + half(n-1)(n-2)c \r
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document.write( "a = value of first term in sequence
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document.write( "d = first difference between the first two numbers
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document.write( "c = is the change between one difference and the next\r
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document.write( "a = 481
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document.write( "d = 600
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document.write( "c = 240\r
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document.write( "Changing Difference Sequence:
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document.write( "481, 1081, 1921, 3001, 4321 Sequence
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document.write( " 600 840 1080 1320 first difference
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document.write( " 240 240 240 Second difference\r
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document.write( "I have tried for several hours to figure it out for my own results but have just got frustrated. I need to solve the nth term formula for this changing difference sequence to move on with my coursework. Thank you so much for any help! \r
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Algebra.Com's Answer #520570 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 120n^2 + 240n + 121 \n" ); document.write( " |