document.write( "Question 863621: An amount of $1000 is invested and interest is compounded continuously. Find the annual relative growth rate for the investment to grow to $2500 in 10 years. Solve algebraically. \n" ); document.write( "
Algebra.Com's Answer #520531 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "A = Pe^(rt)
\n" ); document.write( "\"2500%2F1000+=+e%5E%2810r%29\"
\n" ); document.write( "ln(2.5)/10 = r = 9.16% \n" ); document.write( "
\n" );