document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72766>Question 72766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I hope you can help.\r<BR>\n" );
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document.write( "My question is 5(2x-1)=4(4-x) I know the answer to this but I cannot figure out how you get to it.  The problem I seem to be having is when do two minus signs turn to a plus.  I have tried this equation in both ways and can only get the answer if the minus signs change.\r<BR>\n" );
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document.write( "Also very confusing was one of the previous questions had two minus signs and would not work unless they remained as minus signs.\r<BR>\n" );
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document.write( "So really the question for me is when do you change the signs?\r<BR>\n" );
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document.write( "Thankyou very much\r<BR>\n" );
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document.write( "Scott Young <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #52053 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=52053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5(2x-1)=4(4-x)<BR>\n" );
document.write( "10x-5=16-4x<BR>\n" );
document.write( "Add 4x to both sides to get:<BR>\n" );
document.write( "14x-5=16<BR>\n" );
document.write( "Add 5 to both sides to get:<BR>\n" );
document.write( "14x=21<BR>\n" );
document.write( "Divide both sides by 14 to get<BR>\n" );
document.write( "x=21/14<BR>\n" );
document.write( "Reduce 21/14 to get:<BR>\n" );
document.write( "x=3/2<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );