document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=863642>Question 863642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The pth term of an AP is (3p-1)/6. The sum of the first n terms of the AP is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520529 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The pth term of an AP is (3p-1)/6. The sum of the first n terms of the AP is?<BR>\n" );
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document.write( "Sum Formula: S(n) = (n/2)(a(1)+a(n)<BR>\n" );
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document.write( "a(1) = (3-1)/6 = 1/2<BR>\n" );
document.write( "a(n) = (3n-1)/6<BR>\n" );
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document.write( "S(n) = (n/2)[(1/2)+(3n-1)/6]<BR>\n" );
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document.write( "= (n/2)[(3+3n-1)/6]<BR>\n" );
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document.write( "= (n/2)(3n+2)/6<BR>\n" );
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document.write( "= (3n^2+2n)/12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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