document.write( "Question 863633: Chelsea drove 300 miles north, average 55 she slowed down get average 15 mph, if the trip takes 6 hours at how many miles did she drive reduced?
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Algebra.Com's Answer #520523 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Chelsea drove 300 miles north, average 55 she slowed down get average 15 mph, if the trip takes 6 hours at how many miles did she drive reduced? \n" ); document.write( "------ \n" ); document.write( "Time at 55 mph:: 300/55 = 5.45 hours \n" ); document.write( "---- \n" ); document.write( "Time at 15 mph: (6-5.45) = 0.55 hrs \n" ); document.write( "----- \n" ); document.write( "Distance at reduced speed:: 0.55*15 = 8.25 miles \n" ); document.write( "-------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |