document.write( "Question 863633: Chelsea drove 300 miles north, average 55 she slowed down get average 15 mph, if the trip takes 6 hours at how many miles did she drive reduced?
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Algebra.Com's Answer #520523 by stanbon(75887)\"\" \"About 
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Chelsea drove 300 miles north, average 55 she slowed down get average 15 mph, if the trip takes 6 hours at how many miles did she drive reduced?
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\n" ); document.write( "Time at 55 mph:: 300/55 = 5.45 hours
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\n" ); document.write( "Time at 15 mph: (6-5.45) = 0.55 hrs
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\n" ); document.write( "Distance at reduced speed:: 0.55*15 = 8.25 miles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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