document.write( "Question 72679: If (a) does not equal (b), solve for x in terms of (a) and (b):
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document.write( "x^2+ax=-b(a+x) \n" );
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Algebra.Com's Answer #52052 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! If (a) does not equal (b), solve for x in terms of (a) and (b): \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By inspection, we can see that the equation can be factored because the B coefficient is the sum of the product of the C coefficient. This is always the case, when A=1. So we have:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " CK \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps-------------------ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |