document.write( "Question 863341: 2 years ago Stephanie was 4 times as old as Jennifer.
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document.write( "Two years from now Stephanie will be 3 times as old as Jennifer.
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document.write( " a)How old are Stephanie and Jennifer now?
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document.write( "b)In how many years will Stephanie be 2 times as old as Jennifer.
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document.write( "c)How old was Stephanie when Jennifer was born? \n" );
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Algebra.Com's Answer #520402 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! s+2=3*(j+2) \n" ); document.write( "s+2=3j+6\r \n" ); document.write( "\n" ); document.write( "s-2=4*(j-2) \n" ); document.write( "s-2=4j-8 \n" ); document.write( "s+2=3j+6 \n" ); document.write( "2s=7j-2 \n" ); document.write( "s=3.5j-1 \n" ); document.write( "3.5j+1=3j+6 \n" ); document.write( ".5j=5 \n" ); document.write( "j=10 \n" ); document.write( "s=3.5j-1 \n" ); document.write( "s=35-1 \n" ); document.write( "s=34 \n" ); document.write( "a) j=10 s=34 \n" ); document.write( "b)34+x=2*(10+x) \n" ); document.write( "34+x=20+2x \n" ); document.write( "14=x \n" ); document.write( "10+14=24 \n" ); document.write( "34+14=48 \n" ); document.write( "c) \n" ); document.write( "34-10=24\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |