document.write( "Question 863264: \r
\n" ); document.write( "\n" ); document.write( "A total of $12,000 was invested. Part of the money was invested at 4% and the rest was invested at 5%. If the interest for one year is $560, how much was invested at each rate?
\n" ); document.write( "

Algebra.Com's Answer #520378 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.05X+.04(12,000-X)=560
\n" ); document.write( ".05X+480-.04X=560
\n" ); document.write( ".01X=560-480
\n" ); document.write( ".01X=80
\n" ); document.write( "X=80/.01
\n" ); document.write( "X=$8,000 AMOUNT INVESTED @ 5%.
\n" ); document.write( "12,000-8,000=$4,000 AMOUNT INVESTED @ 4%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".05*8,000+.04*4,000=560
\n" ); document.write( "400+160=560
\n" ); document.write( "560=560
\n" ); document.write( "
\n" );