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document.write( "A total of $12,000 was invested. Part of the money was invested at 4% and the rest was invested at 5%. If the interest for one year is $560, how much was invested at each rate? \n" );
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Algebra.Com's Answer #520378 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .05X+.04(12,000-X)=560 \n" ); document.write( ".05X+480-.04X=560 \n" ); document.write( ".01X=560-480 \n" ); document.write( ".01X=80 \n" ); document.write( "X=80/.01 \n" ); document.write( "X=$8,000 AMOUNT INVESTED @ 5%. \n" ); document.write( "12,000-8,000=$4,000 AMOUNT INVESTED @ 4%. \n" ); document.write( "PROOF: \n" ); document.write( ".05*8,000+.04*4,000=560 \n" ); document.write( "400+160=560 \n" ); document.write( "560=560 \n" ); document.write( " |