document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=863357>Question 863357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the unit circle to find the value of cos(2&#960;/3) and even or odd trigonometric functions to find the value of cos(-2&#960;/3).\r<BR>\n" );
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document.write( "So first what I did was find the cos given on the unit circle which gives me (-1/2,sqrt(3)/2). Cos represents x of the point so cos(2&#960;/3) is -1/2. \r<BR>\n" );
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document.write( "Then I don't know how to use even or odd functions to find the second cos.\r<BR>\n" );
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document.write( "Thank you. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #520350 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=520350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Fundamental Identity<BR>\n" );
document.write( " cos(-&#952;) = cos &#952;,          </SPAN>\n" );
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